j^2-4j-21=0

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Solution for j^2-4j-21=0 equation:


Simplifying
j2 + -4j + -21 = 0

Reorder the terms:
-21 + -4j + j2 = 0

Solving
-21 + -4j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-3 + -1j)(7 + -1j) = 0

Subproblem 1

Set the factor '(-3 + -1j)' equal to zero and attempt to solve: Simplifying -3 + -1j = 0 Solving -3 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1j = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1j = 0 + 3 -1j = 0 + 3 Combine like terms: 0 + 3 = 3 -1j = 3 Divide each side by '-1'. j = -3 Simplifying j = -3

Subproblem 2

Set the factor '(7 + -1j)' equal to zero and attempt to solve: Simplifying 7 + -1j = 0 Solving 7 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1j = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1j = 0 + -7 -1j = 0 + -7 Combine like terms: 0 + -7 = -7 -1j = -7 Divide each side by '-1'. j = 7 Simplifying j = 7

Solution

j = {-3, 7}

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